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Oracle Database SQL Sample Questions (Q258-Q263):

NEW QUESTION # 258
Which two statements are true about the data dictionary?

A. Views with the prefix all_ display metadata for objects to which the current user has access.
B. The data dictionary does not store metadata in tables.
C. Views with the prefix all_, dba_ and useb_ are not all available for every type of metadata.
D. Views with the prefix dba_ display only metadata for objects in the SYS schema.
E. The data dictionary is accessible when the database is closed.

Answer: A,C

Explanation:
The data dictionary contains metadata (data about data) about the database and its objects.
A). False. DBA_ views display metadata for objects accessible to the database administrator, not only for the SYS schema.
B). True. ALL_ views display information about all the objects that the current user has access to. This does not necessarily mean the user has privileges on these objects, only that the user can see them.
C). False. The data dictionary is not accessible when the database is closed because it requires the database to be open in order to access the system tables.
D). True. Not all types of metadata are available in all three prefixes (ALL_, DBA_, USER_). Some specific metadata might only be available in one or two of these view types.
E). False. The data dictionary stores metadata in tables. The various views (ALL_, DBA_, USER_, etc.) provide different perspectives on this data.
References:
* Oracle Documentation on Data Dictionary and Dynamic Performance Views:
https://docs.oracle.com/cd/B28359_01/server.111/b28310/datadict.htm

NEW QUESTION # 259
You are designing the structure of a table in which two columns have the specifications:
COMPONENT_ID - must be able to contain a maximum of 12 alphanumeric characters and uniquely identify the row
EXECUTION_DATETIME - contains Century, Year, Month, Day, Hour, Minute, Second to the maximum precision and is used for calculations and comparisons between components.
Which two options define the data types that satisfy these requirements most efficiently?

A. The COMPONENT_ID must be of ROWID data type.
B. The EXECUTION _DATETIME must be of TIMESTAMP data type.
C. The COMPONENT_ID column must be of CHAR data type.
D. The COMPONENT_ID must be of VARCHAR2 data type.
E. The EXECUTION_DATATIME must be of DATE data type.
F. The EXECUTION_DATETIME must be of INTERVAL DAY TO SECOND data type.

Answer: D,E

NEW QUESTION # 260
Which statement is true regarding the INTERSECT operator?

A. The names of columns in all SELECT statements must be identical.
B. It ignores NULL values.
C. The number of columns and data types must be identical for all SELECT statements in the query.
D. Reversing the order of the intersected tables alters the result.

Answer: C

Explanation:
Explanation
INTERSECT Returns only the rows that occur in both queries' result sets, sorting them and removing duplicates.
The columns in the queries that make up a compound query can have different names, but the output result set will use the names of the columns in the first query.
References:
http://oraclexpert.com/using-the-set-operators/

NEW QUESTION # 261
Which two statements are true regarding the DELETEand TRUNCATEcommands? (Choose two.)

A. DELETEcan be used to remove rows only for tables that are parents for a child table that has a referential integrity constraint referring to the parent.
B. DELETEcan be used to remove data from specific columns as well as complete rows.
C. DELETEcan be used to remove rows from multiple tables in one statement.
D. DELETEcan be used to remove rows from only one table in one statement.
E. DELETEand TRUNCATEcan be used for tables that are parents for a child table that has a referential integrity constraint having an ON DELETErule.

Answer: D,E

NEW QUESTION # 262
Examine the data in the ORDERS table:

Examine the data in the INVOICES table:

Examine this query:
SELECT order_ id, order_ date FROM orders
INTERSECT
SELECT order_ 1d, order_ date FROM invoices;
Which two rows will it return?

A. 3 01-JAN-2019
B. 1 <null>
C. 4 01-FEB-2019
D. 5 01-MAR-2019
E. 3 <null>
F. 2 <null>

Answer: B,C

Explanation:
The INTERSECT operator in SQL returns the results that are common to both of the SELECT statements. It functions similarly to a set intersection in mathematics. When comparing rows for the INTERSECT operation, Oracle Database uses all the expressions in the SELECT lists to derive the result set. NULL values are considered equal for the INTERSECT operator.
Evaluating the provided data from the ORDERS and INVOICES tables, let's see which rows have the same ORDER_ID and ORDER_DATE in both tables:
A: Order ID 3 has a NULL order date in the ORDERS table and does not match with any row in the INVOICES table, so it will not be returned.
B: Order ID 2 has a NULL order date in the ORDERS table but has a non-NULL order date in the INVOICES table, so it will not be returned.
C: Order ID 1 has a NULL order date in both tables, but INTERSECT considers NULLs as equal, so this will be returned.
D: Order ID 5 has a date of 01-MAR-2019 in the ORDERS table and 01-APR-2019 in the INVOICES table, so it will not be returned since the dates do not match.
E: Order ID 4 has a date of 01-FEB-2019 in both tables, so this row will be returned as it matches in both.
F: Order ID 3 has a NULL order date in the ORDERS table but has 01-JAN-2019 in the INVOICES table, so it will not be returned.
Based on this analysis, the query will return:
Order ID 1 with a NULL order date.
Order ID 4 with an order date of 01-FEB-2019.
So the correct answer is:

NEW QUESTION # 263
......

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